7(3c+1)=5c-2(c+3)

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Solution for 7(3c+1)=5c-2(c+3) equation:


Simplifying
7(3c + 1) = 5c + -2(c + 3)

Reorder the terms:
7(1 + 3c) = 5c + -2(c + 3)
(1 * 7 + 3c * 7) = 5c + -2(c + 3)
(7 + 21c) = 5c + -2(c + 3)

Reorder the terms:
7 + 21c = 5c + -2(3 + c)
7 + 21c = 5c + (3 * -2 + c * -2)
7 + 21c = 5c + (-6 + -2c)

Reorder the terms:
7 + 21c = -6 + 5c + -2c

Combine like terms: 5c + -2c = 3c
7 + 21c = -6 + 3c

Solving
7 + 21c = -6 + 3c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-3c' to each side of the equation.
7 + 21c + -3c = -6 + 3c + -3c

Combine like terms: 21c + -3c = 18c
7 + 18c = -6 + 3c + -3c

Combine like terms: 3c + -3c = 0
7 + 18c = -6 + 0
7 + 18c = -6

Add '-7' to each side of the equation.
7 + -7 + 18c = -6 + -7

Combine like terms: 7 + -7 = 0
0 + 18c = -6 + -7
18c = -6 + -7

Combine like terms: -6 + -7 = -13
18c = -13

Divide each side by '18'.
c = -0.7222222222

Simplifying
c = -0.7222222222

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