7(3c+4)=2(3c-1)

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Solution for 7(3c+4)=2(3c-1) equation:


Simplifying
7(3c + 4) = 2(3c + -1)

Reorder the terms:
7(4 + 3c) = 2(3c + -1)
(4 * 7 + 3c * 7) = 2(3c + -1)
(28 + 21c) = 2(3c + -1)

Reorder the terms:
28 + 21c = 2(-1 + 3c)
28 + 21c = (-1 * 2 + 3c * 2)
28 + 21c = (-2 + 6c)

Solving
28 + 21c = -2 + 6c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-6c' to each side of the equation.
28 + 21c + -6c = -2 + 6c + -6c

Combine like terms: 21c + -6c = 15c
28 + 15c = -2 + 6c + -6c

Combine like terms: 6c + -6c = 0
28 + 15c = -2 + 0
28 + 15c = -2

Add '-28' to each side of the equation.
28 + -28 + 15c = -2 + -28

Combine like terms: 28 + -28 = 0
0 + 15c = -2 + -28
15c = -2 + -28

Combine like terms: -2 + -28 = -30
15c = -30

Divide each side by '15'.
c = -2

Simplifying
c = -2

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