7(3n+1)=6(6n+5)+3

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Solution for 7(3n+1)=6(6n+5)+3 equation:



7(3n+1)=6(6n+5)+3
We move all terms to the left:
7(3n+1)-(6(6n+5)+3)=0
We multiply parentheses
21n-(6(6n+5)+3)+7=0
We calculate terms in parentheses: -(6(6n+5)+3), so:
6(6n+5)+3
We multiply parentheses
36n+30+3
We add all the numbers together, and all the variables
36n+33
Back to the equation:
-(36n+33)
We get rid of parentheses
21n-36n-33+7=0
We add all the numbers together, and all the variables
-15n-26=0
We move all terms containing n to the left, all other terms to the right
-15n=26
n=26/-15
n=-1+11/15

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