7(3n+2)=7(6n+3)+3

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Solution for 7(3n+2)=7(6n+3)+3 equation: 



7(3n+2)=7(6n+3)+3

We move all terms to the left:

7(3n+2)-(7(6n+3)+3)=0

We multiply parentheses

21n-(7(6n+3)+3)+14=0



We calculate terms in parentheses: -(7(6n+3)+3), so:

7(6n+3)+3

We multiply parentheses

42n+21+3

We add all the numbers together, and all the variables

42n+24

Back to the equation:

-(42n+24)



We get rid of parentheses

21n-42n-24+14=0

We add all the numbers together, and all the variables

-21n-10=0

We move all terms containing n to the left, all other terms to the right

-21n=10

n=10/-21

n=-10/21

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