7(3n+3)=2(7n-4)+8n

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Solution for 7(3n+3)=2(7n-4)+8n equation: 



7(3n+3)=2(7n-4)+8n

We move all terms to the left:

7(3n+3)-(2(7n-4)+8n)=0

We multiply parentheses

21n-(2(7n-4)+8n)+21=0



We calculate terms in parentheses: -(2(7n-4)+8n), so:

2(7n-4)+8n

We add all the numbers together, and all the variables

8n+2(7n-4)

We multiply parentheses

8n+14n-8

We add all the numbers together, and all the variables

22n-8

Back to the equation:

-(22n-8)



We get rid of parentheses

21n-22n+8+21=0

We add all the numbers together, and all the variables

-1n+29=0

We move all terms containing n to the left, all other terms to the right

-n=-29

n=-29/-1

n=+29

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