7(3n+5)=6(6n+4)+9

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Solution for 7(3n+5)=6(6n+4)+9 equation:



7(3n+5)=6(6n+4)+9
We move all terms to the left:
7(3n+5)-(6(6n+4)+9)=0
We multiply parentheses
21n-(6(6n+4)+9)+35=0
We calculate terms in parentheses: -(6(6n+4)+9), so:
6(6n+4)+9
We multiply parentheses
36n+24+9
We add all the numbers together, and all the variables
36n+33
Back to the equation:
-(36n+33)
We get rid of parentheses
21n-36n-33+35=0
We add all the numbers together, and all the variables
-15n+2=0
We move all terms containing n to the left, all other terms to the right
-15n=-2
n=-2/-15
n=2/15

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