7(3n-2)+5=6(2n-1)+24

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Solution for 7(3n-2)+5=6(2n-1)+24 equation: 



7(3n-2)+5=6(2n-1)+24

We move all terms to the left:

7(3n-2)+5-(6(2n-1)+24)=0

We multiply parentheses

21n-(6(2n-1)+24)-14+5=0



We calculate terms in parentheses: -(6(2n-1)+24), so:

6(2n-1)+24

We multiply parentheses

12n-6+24

We add all the numbers together, and all the variables

12n+18

Back to the equation:

-(12n+18)



We add all the numbers together, and all the variables

21n-(12n+18)-9=0

We get rid of parentheses

21n-12n-18-9=0

We add all the numbers together, and all the variables

9n-27=0

We move all terms containing n to the left, all other terms to the right

9n=27

n=27/9

n=3

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