7(3q-10)=11(3q-2)

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Solution for 7(3q-10)=11(3q-2) equation:


Simplifying
7(3q + -10) = 11(3q + -2)

Reorder the terms:
7(-10 + 3q) = 11(3q + -2)
(-10 * 7 + 3q * 7) = 11(3q + -2)
(-70 + 21q) = 11(3q + -2)

Reorder the terms:
-70 + 21q = 11(-2 + 3q)
-70 + 21q = (-2 * 11 + 3q * 11)
-70 + 21q = (-22 + 33q)

Solving
-70 + 21q = -22 + 33q

Solving for variable 'q'.

Move all terms containing q to the left, all other terms to the right.

Add '-33q' to each side of the equation.
-70 + 21q + -33q = -22 + 33q + -33q

Combine like terms: 21q + -33q = -12q
-70 + -12q = -22 + 33q + -33q

Combine like terms: 33q + -33q = 0
-70 + -12q = -22 + 0
-70 + -12q = -22

Add '70' to each side of the equation.
-70 + 70 + -12q = -22 + 70

Combine like terms: -70 + 70 = 0
0 + -12q = -22 + 70
-12q = -22 + 70

Combine like terms: -22 + 70 = 48
-12q = 48

Divide each side by '-12'.
q = -4

Simplifying
q = -4

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