7(3q-5)-7q=7(2q-8)

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Solution for 7(3q-5)-7q=7(2q-8) equation:


Simplifying
7(3q + -5) + -7q = 7(2q + -8)

Reorder the terms:
7(-5 + 3q) + -7q = 7(2q + -8)
(-5 * 7 + 3q * 7) + -7q = 7(2q + -8)
(-35 + 21q) + -7q = 7(2q + -8)

Combine like terms: 21q + -7q = 14q
-35 + 14q = 7(2q + -8)

Reorder the terms:
-35 + 14q = 7(-8 + 2q)
-35 + 14q = (-8 * 7 + 2q * 7)
-35 + 14q = (-56 + 14q)

Add '-14q' to each side of the equation.
-35 + 14q + -14q = -56 + 14q + -14q

Combine like terms: 14q + -14q = 0
-35 + 0 = -56 + 14q + -14q
-35 = -56 + 14q + -14q

Combine like terms: 14q + -14q = 0
-35 = -56 + 0
-35 = -56

Solving
-35 = -56

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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