7(3r-1)+(r+5)=-52

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Solution for 7(3r-1)+(r+5)=-52 equation: 



7(3r-1)+(r+5)=-52

We move all terms to the left:

7(3r-1)+(r+5)-(-52)=0

We add all the numbers together, and all the variables

7(3r-1)+(r+5)+52=0

We multiply parentheses

21r+(r+5)-7+52=0

We get rid of parentheses

21r+r+5-7+52=0

We add all the numbers together, and all the variables

22r+50=0

We move all terms containing r to the left, all other terms to the right

22r=-50

r=-50/22

r=-2+3/11

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