7(3t-2)+5=6(2t-1)+24

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Solution for 7(3t-2)+5=6(2t-1)+24 equation: 



7(3t-2)+5=6(2t-1)+24

We move all terms to the left:

7(3t-2)+5-(6(2t-1)+24)=0

We multiply parentheses

21t-(6(2t-1)+24)-14+5=0



We calculate terms in parentheses: -(6(2t-1)+24), so:

6(2t-1)+24

We multiply parentheses

12t-6+24

We add all the numbers together, and all the variables

12t+18

Back to the equation:

-(12t+18)



We add all the numbers together, and all the variables

21t-(12t+18)-9=0

We get rid of parentheses

21t-12t-18-9=0

We add all the numbers together, and all the variables

9t-27=0

We move all terms containing t to the left, all other terms to the right

9t=27

t=27/9

t=3

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