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7(3x+1)-14(x+3)=8(3x-1)+16(3-2x)
We move all terms to the left:
7(3x+1)-14(x+3)-(8(3x-1)+16(3-2x))=0
We add all the numbers together, and all the variables
7(3x+1)-14(x+3)-(8(3x-1)+16(-2x+3))=0
We multiply parentheses
21x-14x-(8(3x-1)+16(-2x+3))+7-42=0
We calculate terms in parentheses: -(8(3x-1)+16(-2x+3)), so:We add all the numbers together, and all the variables
8(3x-1)+16(-2x+3)
We multiply parentheses
24x-32x-8+48
We add all the numbers together, and all the variables
-8x+40
Back to the equation:
-(-8x+40)
7x-(-8x+40)-35=0
We get rid of parentheses
7x+8x-40-35=0
We add all the numbers together, and all the variables
15x-75=0
We move all terms containing x to the left, all other terms to the right
15x=75
x=75/15
x=5
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