7(3x+1)-18=3(4x-2)+13

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Solution for 7(3x+1)-18=3(4x-2)+13 equation: 



7(3x+1)-18=3(4x-2)+13

We move all terms to the left:

7(3x+1)-18-(3(4x-2)+13)=0

We multiply parentheses

21x-(3(4x-2)+13)+7-18=0



We calculate terms in parentheses: -(3(4x-2)+13), so:

3(4x-2)+13

We multiply parentheses

12x-6+13

We add all the numbers together, and all the variables

12x+7

Back to the equation:

-(12x+7)



We add all the numbers together, and all the variables

21x-(12x+7)-11=0

We get rid of parentheses

21x-12x-7-11=0

We add all the numbers together, and all the variables

9x-18=0

We move all terms containing x to the left, all other terms to the right

9x=18

x=18/9

x=2

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