7(3x+1)=(4x+2x+1x)+791

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Solution for 7(3x+1)=(4x+2x+1x)+791 equation: 



7(3x+1)=(4x+2x+1x)+791

We move all terms to the left:

7(3x+1)-((4x+2x+1x)+791)=0

We add all the numbers together, and all the variables

7(3x+1)-((+7x)+791)=0

We multiply parentheses

21x-((+7x)+791)+7=0



We calculate terms in parentheses: -((+7x)+791), so:

(+7x)+791

We get rid of parentheses

7x+791

Back to the equation:

-(7x+791)



We get rid of parentheses

21x-7x-791+7=0

We add all the numbers together, and all the variables

14x-784=0

We move all terms containing x to the left, all other terms to the right

14x=784

x=784/14

x=56

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