7(3x+1)=7(9x+7)+5

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Solution for 7(3x+1)=7(9x+7)+5 equation: 



7(3x+1)=7(9x+7)+5

We move all terms to the left:

7(3x+1)-(7(9x+7)+5)=0

We multiply parentheses

21x-(7(9x+7)+5)+7=0



We calculate terms in parentheses: -(7(9x+7)+5), so:

7(9x+7)+5

We multiply parentheses

63x+49+5

We add all the numbers together, and all the variables

63x+54

Back to the equation:

-(63x+54)



We get rid of parentheses

21x-63x-54+7=0

We add all the numbers together, and all the variables

-42x-47=0

We move all terms containing x to the left, all other terms to the right

-42x=47

x=47/-42

x=-1+5/42

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