7(3x+1)=8(2x-5)

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Solution for 7(3x+1)=8(2x-5) equation: 



7(3x+1)=8(2x-5)

We move all terms to the left:

7(3x+1)-(8(2x-5))=0

We multiply parentheses

21x-(8(2x-5))+7=0



We calculate terms in parentheses: -(8(2x-5)), so:

8(2x-5)

We multiply parentheses

16x-40

Back to the equation:

-(16x-40)



We get rid of parentheses

21x-16x+40+7=0

We add all the numbers together, and all the variables

5x+47=0

We move all terms containing x to the left, all other terms to the right

5x=-47

x=-47/5

x=-9+2/5

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