7(3x+2)=6(x-3)-20

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Solution for 7(3x+2)=6(x-3)-20 equation: 



7(3x+2)=6(x-3)-20

We move all terms to the left:

7(3x+2)-(6(x-3)-20)=0

We multiply parentheses

21x-(6(x-3)-20)+14=0



We calculate terms in parentheses: -(6(x-3)-20), so:

6(x-3)-20

We multiply parentheses

6x-18-20

We add all the numbers together, and all the variables

6x-38

Back to the equation:

-(6x-38)



We get rid of parentheses

21x-6x+38+14=0

We add all the numbers together, and all the variables

15x+52=0

We move all terms containing x to the left, all other terms to the right

15x=-52

x=-52/15

x=-3+7/15

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