7(3x+4)=8(2x+5)=13

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Solution for 7(3x+4)=8(2x+5)=13 equation: 



7(3x+4)=8(2x+5)=13

We move all terms to the left:

7(3x+4)-(8(2x+5))=0

We multiply parentheses

21x-(8(2x+5))+28=0



We calculate terms in parentheses: -(8(2x+5)), so:

8(2x+5)

We multiply parentheses

16x+40

Back to the equation:

-(16x+40)



We get rid of parentheses

21x-16x-40+28=0

We add all the numbers together, and all the variables

5x-12=0

We move all terms containing x to the left, all other terms to the right

5x=12

x=12/5

x=2+2/5

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