7(3x+4)=8(5x-2)

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Solution for 7(3x+4)=8(5x-2) equation: 



7(3x+4)=8(5x-2)

We move all terms to the left:

7(3x+4)-(8(5x-2))=0

We multiply parentheses

21x-(8(5x-2))+28=0



We calculate terms in parentheses: -(8(5x-2)), so:

8(5x-2)

We multiply parentheses

40x-16

Back to the equation:

-(40x-16)



We get rid of parentheses

21x-40x+16+28=0

We add all the numbers together, and all the variables

-19x+44=0

We move all terms containing x to the left, all other terms to the right

-19x=-44

x=-44/-19

x=2+6/19

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