7(3x+4)=8(5x-2)

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Solution for 7(3x+4)=8(5x-2) equation:



7(3x+4)=8(5x-2)
We move all terms to the left:
7(3x+4)-(8(5x-2))=0
We multiply parentheses
21x-(8(5x-2))+28=0
We calculate terms in parentheses: -(8(5x-2)), so:
8(5x-2)
We multiply parentheses
40x-16
Back to the equation:
-(40x-16)
We get rid of parentheses
21x-40x+16+28=0
We add all the numbers together, and all the variables
-19x+44=0
We move all terms containing x to the left, all other terms to the right
-19x=-44
x=-44/-19
x=2+6/19

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