7(3x+4)=9(6x+7)+8

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Solution for 7(3x+4)=9(6x+7)+8 equation:



7(3x+4)=9(6x+7)+8
We move all terms to the left:
7(3x+4)-(9(6x+7)+8)=0
We multiply parentheses
21x-(9(6x+7)+8)+28=0
We calculate terms in parentheses: -(9(6x+7)+8), so:
9(6x+7)+8
We multiply parentheses
54x+63+8
We add all the numbers together, and all the variables
54x+71
Back to the equation:
-(54x+71)
We get rid of parentheses
21x-54x-71+28=0
We add all the numbers together, and all the variables
-33x-43=0
We move all terms containing x to the left, all other terms to the right
-33x=43
x=43/-33
x=-1+10/33

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