7(3x+5)=4(2x-2)

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Solution for 7(3x+5)=4(2x-2) equation: 



7(3x+5)=4(2x-2)

We move all terms to the left:

7(3x+5)-(4(2x-2))=0

We multiply parentheses

21x-(4(2x-2))+35=0



We calculate terms in parentheses: -(4(2x-2)), so:

4(2x-2)

We multiply parentheses

8x-8

Back to the equation:

-(8x-8)



We get rid of parentheses

21x-8x+8+35=0

We add all the numbers together, and all the variables

13x+43=0

We move all terms containing x to the left, all other terms to the right

13x=-43

x=-43/13

x=-3+4/13

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