7(3x+9)2=6(2x+31)

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Solution for 7(3x+9)2=6(2x+31) equation: 



7(3x+9)2=6(2x+31)

We move all terms to the left:

7(3x+9)2-(6(2x+31))=0

We multiply parentheses

42x-(6(2x+31))+126=0



We calculate terms in parentheses: -(6(2x+31)), so:

6(2x+31)

We multiply parentheses

12x+186

Back to the equation:

-(12x+186)



We get rid of parentheses

42x-12x-186+126=0

We add all the numbers together, and all the variables

30x-60=0

We move all terms containing x to the left, all other terms to the right

30x=60

x=60/30

x=2

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