7(3x-1)+62=6(2x+7)

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Solution for 7(3x-1)+62=6(2x+7) equation: 



7(3x-1)+62=6(2x+7)

We move all terms to the left:

7(3x-1)+62-(6(2x+7))=0

We multiply parentheses

21x-(6(2x+7))-7+62=0



We calculate terms in parentheses: -(6(2x+7)), so:

6(2x+7)

We multiply parentheses

12x+42

Back to the equation:

-(12x+42)



We add all the numbers together, and all the variables

21x-(12x+42)+55=0

We get rid of parentheses

21x-12x-42+55=0

We add all the numbers together, and all the variables

9x+13=0

We move all terms containing x to the left, all other terms to the right

9x=-13

x=-13/9

x=-1+4/9

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