7(3x-1)-3(4x-4)=4(2x+5)-19

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Solution for 7(3x-1)-3(4x-4)=4(2x+5)-19 equation: 



7(3x-1)-3(4x-4)=4(2x+5)-19

We move all terms to the left:

7(3x-1)-3(4x-4)-(4(2x+5)-19)=0

We multiply parentheses

21x-12x-(4(2x+5)-19)-7+12=0



We calculate terms in parentheses: -(4(2x+5)-19), so:

4(2x+5)-19

We multiply parentheses

8x+20-19

We add all the numbers together, and all the variables

8x+1

Back to the equation:

-(8x+1)



We add all the numbers together, and all the variables

9x-(8x+1)+5=0

We get rid of parentheses

9x-8x-1+5=0

We add all the numbers together, and all the variables

x+4=0

We move all terms containing x to the left, all other terms to the right

x=-4

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