7(3x-1)6(2x+3)=8(x-2)+1

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Solution for 7(3x-1)6(2x+3)=8(x-2)+1 equation: 



7(3x-1)6(2x+3)=8(x-2)+1

We move all terms to the left:

7(3x-1)6(2x+3)-(8(x-2)+1)=0



We calculate terms in parentheses: -(8(x-2)+1), so:

8(x-2)+1

We multiply parentheses

8x-16+1

We add all the numbers together, and all the variables

8x-15

Back to the equation:

-(8x-15)



We get rid of parentheses

7(3x-1)6(2x+3)-8x+15=0

We add all the numbers together, and all the variables

-8x+7(3x-1)6(2x+3)+15=0

We move all terms containing x to the left, all other terms to the right

-8x+7(3x-1)6(2x+3)=-15

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