7(3x-2)+4(10-3x)=4(2x+3)-10

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Solution for 7(3x-2)+4(10-3x)=4(2x+3)-10 equation: 



7(3x-2)+4(10-3x)=4(2x+3)-10

We move all terms to the left:

7(3x-2)+4(10-3x)-(4(2x+3)-10)=0

We add all the numbers together, and all the variables

7(3x-2)+4(-3x+10)-(4(2x+3)-10)=0

We multiply parentheses

21x-12x-(4(2x+3)-10)-14+40=0



We calculate terms in parentheses: -(4(2x+3)-10), so:

4(2x+3)-10

We multiply parentheses

8x+12-10

We add all the numbers together, and all the variables

8x+2

Back to the equation:

-(8x+2)



We add all the numbers together, and all the variables

9x-(8x+2)+26=0

We get rid of parentheses

9x-8x-2+26=0

We add all the numbers together, and all the variables

x+24=0

We move all terms containing x to the left, all other terms to the right

x=-24

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