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7(3x-2)+5=6(2x-1)+
We move all terms to the left:
7(3x-2)+5-(6(2x-1)+)=0
We multiply parentheses
21x-(6(2x-1)+)-14+5=0
We calculate terms in parentheses: -(6(2x-1)+), so:We add all the numbers together, and all the variables
6(2x-1)+
We add all the numbers together, and all the variables
6(2x-1)
We multiply parentheses
12x-6
Back to the equation:
-(12x-6)
21x-(12x-6)-9=0
We get rid of parentheses
21x-12x+6-9=0
We add all the numbers together, and all the variables
9x-3=0
We move all terms containing x to the left, all other terms to the right
9x=3
x=3/9
x=1/3
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