7(3x-2)=3(2x+3)-5(2-3x)

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Solution for 7(3x-2)=3(2x+3)-5(2-3x) equation: 



7(3x-2)=3(2x+3)-5(2-3x)

We move all terms to the left:

7(3x-2)-(3(2x+3)-5(2-3x))=0

We add all the numbers together, and all the variables

7(3x-2)-(3(2x+3)-5(-3x+2))=0

We multiply parentheses

21x-(3(2x+3)-5(-3x+2))-14=0



We calculate terms in parentheses: -(3(2x+3)-5(-3x+2)), so:

3(2x+3)-5(-3x+2)

We multiply parentheses

6x+15x+9-10

We add all the numbers together, and all the variables

21x-1

Back to the equation:

-(21x-1)



We get rid of parentheses

21x-21x+1-14=0

We add all the numbers together, and all the variables

-13!=0

There is no solution for this equation

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