7(3x-2)=3(5x-3)+7

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Solution for 7(3x-2)=3(5x-3)+7 equation: 



7(3x-2)=3(5x-3)+7

We move all terms to the left:

7(3x-2)-(3(5x-3)+7)=0

We multiply parentheses

21x-(3(5x-3)+7)-14=0



We calculate terms in parentheses: -(3(5x-3)+7), so:

3(5x-3)+7

We multiply parentheses

15x-9+7

We add all the numbers together, and all the variables

15x-2

Back to the equation:

-(15x-2)



We get rid of parentheses

21x-15x+2-14=0

We add all the numbers together, and all the variables

6x-12=0

We move all terms containing x to the left, all other terms to the right

6x=12

x=12/6

x=2

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