7(3x-2)=6(4x+4)+4

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Solution for 7(3x-2)=6(4x+4)+4 equation: 



7(3x-2)=6(4x+4)+4

We move all terms to the left:

7(3x-2)-(6(4x+4)+4)=0

We multiply parentheses

21x-(6(4x+4)+4)-14=0



We calculate terms in parentheses: -(6(4x+4)+4), so:

6(4x+4)+4

We multiply parentheses

24x+24+4

We add all the numbers together, and all the variables

24x+28

Back to the equation:

-(24x+28)



We get rid of parentheses

21x-24x-28-14=0

We add all the numbers together, and all the variables

-3x-42=0

We move all terms containing x to the left, all other terms to the right

-3x=42

x=42/-3

x=-14

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