7(3x-2)=6x+16

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Solution for 7(3x-2)=6x+16 equation: 



7(3x-2)=6x+16

We move all terms to the left:

7(3x-2)-(6x+16)=0

We multiply parentheses

21x-(6x+16)-14=0

We get rid of parentheses

21x-6x-16-14=0

We add all the numbers together, and all the variables

15x-30=0

We move all terms containing x to the left, all other terms to the right

15x=30

x=30/15

x=2

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