7(3x-20)-1=6(5x-40)

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Solution for 7(3x-20)-1=6(5x-40) equation: 



7(3x-20)-1=6(5x-40)

We move all terms to the left:

7(3x-20)-1-(6(5x-40))=0

We multiply parentheses

21x-(6(5x-40))-140-1=0



We calculate terms in parentheses: -(6(5x-40)), so:

6(5x-40)

We multiply parentheses

30x-240

Back to the equation:

-(30x-240)



We add all the numbers together, and all the variables

21x-(30x-240)-141=0

We get rid of parentheses

21x-30x+240-141=0

We add all the numbers together, and all the variables

-9x+99=0

We move all terms containing x to the left, all other terms to the right

-9x=-99

x=-99/-9

x=+11

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