7(3x-4)=2x+3(x-8)

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Solution for 7(3x-4)=2x+3(x-8) equation: 



7(3x-4)=2x+3(x-8)

We move all terms to the left:

7(3x-4)-(2x+3(x-8))=0

We multiply parentheses

21x-(2x+3(x-8))-28=0



We calculate terms in parentheses: -(2x+3(x-8)), so:

2x+3(x-8)

We multiply parentheses

2x+3x-24

We add all the numbers together, and all the variables

5x-24

Back to the equation:

-(5x-24)



We get rid of parentheses

21x-5x+24-28=0

We add all the numbers together, and all the variables

16x-4=0

We move all terms containing x to the left, all other terms to the right

16x=4

x=4/16

x=1/4

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