7(3x-4)=4(4x+3)

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Solution for 7(3x-4)=4(4x+3) equation: 



7(3x-4)=4(4x+3)

We move all terms to the left:

7(3x-4)-(4(4x+3))=0

We multiply parentheses

21x-(4(4x+3))-28=0



We calculate terms in parentheses: -(4(4x+3)), so:

4(4x+3)

We multiply parentheses

16x+12

Back to the equation:

-(16x+12)



We get rid of parentheses

21x-16x-12-28=0

We add all the numbers together, and all the variables

5x-40=0

We move all terms containing x to the left, all other terms to the right

5x=40

x=40/5

x=8

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