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7(3x-5)=4(5x+6)
We move all terms to the left:
7(3x-5)-(4(5x+6))=0
We multiply parentheses
21x-(4(5x+6))-35=0
We calculate terms in parentheses: -(4(5x+6)), so:We get rid of parentheses
4(5x+6)
We multiply parentheses
20x+24
Back to the equation:
-(20x+24)
21x-20x-24-35=0
We add all the numbers together, and all the variables
x-59=0
We move all terms containing x to the left, all other terms to the right
x=59
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