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7(3x-5)=4(5x-11)
We move all terms to the left:
7(3x-5)-(4(5x-11))=0
We multiply parentheses
21x-(4(5x-11))-35=0
We calculate terms in parentheses: -(4(5x-11)), so:We get rid of parentheses
4(5x-11)
We multiply parentheses
20x-44
Back to the equation:
-(20x-44)
21x-20x+44-35=0
We add all the numbers together, and all the variables
x+9=0
We move all terms containing x to the left, all other terms to the right
x=-9
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