7(3x-5)=5(x+2)+12

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Solution for 7(3x-5)=5(x+2)+12 equation:


Simplifying
7(3x + -5) = 5(x + 2) + 12

Reorder the terms:
7(-5 + 3x) = 5(x + 2) + 12
(-5 * 7 + 3x * 7) = 5(x + 2) + 12
(-35 + 21x) = 5(x + 2) + 12

Reorder the terms:
-35 + 21x = 5(2 + x) + 12
-35 + 21x = (2 * 5 + x * 5) + 12
-35 + 21x = (10 + 5x) + 12

Reorder the terms:
-35 + 21x = 10 + 12 + 5x

Combine like terms: 10 + 12 = 22
-35 + 21x = 22 + 5x

Solving
-35 + 21x = 22 + 5x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-5x' to each side of the equation.
-35 + 21x + -5x = 22 + 5x + -5x

Combine like terms: 21x + -5x = 16x
-35 + 16x = 22 + 5x + -5x

Combine like terms: 5x + -5x = 0
-35 + 16x = 22 + 0
-35 + 16x = 22

Add '35' to each side of the equation.
-35 + 35 + 16x = 22 + 35

Combine like terms: -35 + 35 = 0
0 + 16x = 22 + 35
16x = 22 + 35

Combine like terms: 22 + 35 = 57
16x = 57

Divide each side by '16'.
x = 3.5625

Simplifying
x = 3.5625

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