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7(3x-6)+9(4x-9)=9(3x-5)
We move all terms to the left:
7(3x-6)+9(4x-9)-(9(3x-5))=0
We multiply parentheses
21x+36x-(9(3x-5))-42-81=0
We calculate terms in parentheses: -(9(3x-5)), so:We add all the numbers together, and all the variables
9(3x-5)
We multiply parentheses
27x-45
Back to the equation:
-(27x-45)
57x-(27x-45)-123=0
We get rid of parentheses
57x-27x+45-123=0
We add all the numbers together, and all the variables
30x-78=0
We move all terms containing x to the left, all other terms to the right
30x=78
x=78/30
x=2+3/5
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