7(3x-7)+5x=3-42+10x

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Solution for 7(3x-7)+5x=3-42+10x equation:



7(3x-7)+5x=3-42+10x
We move all terms to the left:
7(3x-7)+5x-(3-42+10x)=0
We add all the numbers together, and all the variables
7(3x-7)+5x-(10x-39)=0
We add all the numbers together, and all the variables
5x+7(3x-7)-(10x-39)=0
We multiply parentheses
5x+21x-(10x-39)-49=0
We get rid of parentheses
5x+21x-10x+39-49=0
We add all the numbers together, and all the variables
16x-10=0
We move all terms containing x to the left, all other terms to the right
16x=10
x=10/16
x=5/8

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