7(3x-8)+40=4(5x+6)+x-13

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Solution for 7(3x-8)+40=4(5x+6)+x-13 equation: 


Simplifying
7(3x + -8) + 40 = 4(5x + 6) + x + -13

Reorder the terms:
7(-8 + 3x) + 40 = 4(5x + 6) + x + -13
(-8 * 7 + 3x * 7) + 40 = 4(5x + 6) + x + -13
(-56 + 21x) + 40 = 4(5x + 6) + x + -13

Reorder the terms:
-56 + 40 + 21x = 4(5x + 6) + x + -13

Combine like terms: -56 + 40 = -16
-16 + 21x = 4(5x + 6) + x + -13

Reorder the terms:
-16 + 21x = 4(6 + 5x) + x + -13
-16 + 21x = (6 * 4 + 5x * 4) + x + -13
-16 + 21x = (24 + 20x) + x + -13

Reorder the terms:
-16 + 21x = 24 + -13 + 20x + x

Combine like terms: 24 + -13 = 11
-16 + 21x = 11 + 20x + x

Combine like terms: 20x + x = 21x
-16 + 21x = 11 + 21x

Add '-21x' to each side of the equation.
-16 + 21x + -21x = 11 + 21x + -21x

Combine like terms: 21x + -21x = 0
-16 + 0 = 11 + 21x + -21x
-16 = 11 + 21x + -21x

Combine like terms: 21x + -21x = 0
-16 = 11 + 0
-16 = 11

Solving
-16 = 11

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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