7(3y+2/5)+y=1

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Solution for 7(3y+2/5)+y=1 equation:



7(3y+2/5)+y=1
We move all terms to the left:
7(3y+2/5)+y-(1)=0
We add all the numbers together, and all the variables
7(+3y+2/5)+y-1=0
We add all the numbers together, and all the variables
y+7(+3y+2/5)-1=0
We multiply parentheses
y+21y-1+2/5*7=0
We multiply all the terms by the denominator
y*5*7+21y*5*7+2-1*5*7=0
We add all the numbers together, and all the variables
y*5*7+21y*5*7-33=0
Wy multiply elements
35y*7+735y*7-33=0
Wy multiply elements
245y+5145y-33=0
We add all the numbers together, and all the variables
5390y-33=0
We move all terms containing y to the left, all other terms to the right
5390y=33
y=33/5390
y=3/490

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