7(3y+5)=19y+8

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Solution for 7(3y+5)=19y+8 equation: 



7(3y+5)=19y+8

We move all terms to the left:

7(3y+5)-(19y+8)=0

We multiply parentheses

21y-(19y+8)+35=0

We get rid of parentheses

21y-19y-8+35=0

We add all the numbers together, and all the variables

2y+27=0

We move all terms containing y to the left, all other terms to the right

2y=-27

y=-27/2

y=-13+1/2

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