7(3y-2)=21y-12

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Solution for 7(3y-2)=21y-12 equation: 



7(3y-2)=21y-12

We move all terms to the left:

7(3y-2)-(21y-12)=0

We multiply parentheses

21y-(21y-12)-14=0

We get rid of parentheses

21y-21y+12-14=0

We add all the numbers together, and all the variables

-2!=0

There is no solution for this equation

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