7(3y-3)=32

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Solution for 7(3y-3)=32 equation: 



7(3y-3)=32

We move all terms to the left:

7(3y-3)-(32)=0

We multiply parentheses

21y-21-32=0

We add all the numbers together, and all the variables

21y-53=0

We move all terms containing y to the left, all other terms to the right

21y=53

y=53/21

y=2+11/21

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