7(3y-5)=-22(5-y)

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Solution for 7(3y-5)=-22(5-y) equation: 



7(3y-5)=-22(5-y)

We move all terms to the left:

7(3y-5)-(-22(5-y))=0

We add all the numbers together, and all the variables

7(3y-5)-(-22(-1y+5))=0

We multiply parentheses

21y-(-22(-1y+5))-35=0



We calculate terms in parentheses: -(-22(-1y+5)), so:

-22(-1y+5)

We multiply parentheses

22y-110

Back to the equation:

-(22y-110)



We get rid of parentheses

21y-22y+110-35=0

We add all the numbers together, and all the variables

-1y+75=0

We move all terms containing y to the left, all other terms to the right

-y=-75

y=-75/-1

y=+75

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