7(3y-5)=28

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Solution for 7(3y-5)=28 equation: 



7(3y-5)=28

We move all terms to the left:

7(3y-5)-(28)=0

We multiply parentheses

21y-35-28=0

We add all the numbers together, and all the variables

21y-63=0

We move all terms containing y to the left, all other terms to the right

21y=63

y=63/21

y=3

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