7(3y-5)=7+7y

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Solution for 7(3y-5)=7+7y equation: 



7(3y-5)=7+7y

We move all terms to the left:

7(3y-5)-(7+7y)=0

We add all the numbers together, and all the variables

7(3y-5)-(7y+7)=0

We multiply parentheses

21y-(7y+7)-35=0

We get rid of parentheses

21y-7y-7-35=0

We add all the numbers together, and all the variables

14y-42=0

We move all terms containing y to the left, all other terms to the right

14y=42

y=42/14

y=3

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