7(3z+2)-1=21(2-1)+35

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Solution for 7(3z+2)-1=21(2-1)+35 equation:



7(3z+2)-1=21(2-1)+35
We move all terms to the left:
7(3z+2)-1-(21(2-1)+35)=0
We add all the numbers together, and all the variables
7(3z+2)-1-(211+35)=0
We add all the numbers together, and all the variables
7(3z+2)-247=0
We multiply parentheses
21z+14-247=0
We add all the numbers together, and all the variables
21z-233=0
We move all terms containing z to the left, all other terms to the right
21z=233
z=233/21
z=11+2/21

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