7(3z+31)=49

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Solution for 7(3z+31)=49 equation: 



7(3z+31)=49

We move all terms to the left:

7(3z+31)-(49)=0

We multiply parentheses

21z+217-49=0

We add all the numbers together, and all the variables

21z+168=0

We move all terms containing z to the left, all other terms to the right

21z=-168

z=-168/21

z=-8

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