7(4+3x)=2(8x+9)-6

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Solution for 7(4+3x)=2(8x+9)-6 equation: 



7(4+3x)=2(8x+9)-6

We move all terms to the left:

7(4+3x)-(2(8x+9)-6)=0

We add all the numbers together, and all the variables

7(3x+4)-(2(8x+9)-6)=0

We multiply parentheses

21x-(2(8x+9)-6)+28=0



We calculate terms in parentheses: -(2(8x+9)-6), so:

2(8x+9)-6

We multiply parentheses

16x+18-6

We add all the numbers together, and all the variables

16x+12

Back to the equation:

-(16x+12)



We get rid of parentheses

21x-16x-12+28=0

We add all the numbers together, and all the variables

5x+16=0

We move all terms containing x to the left, all other terms to the right

5x=-16

x=-16/5

x=-3+1/5

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